pandas实现手机号号码中间4位匿名化的示例代码_python_

>>> import pandas as pd >>> import numpy as np # 这里需要将手机号所在列在读取时指定类型 >>> df = pd.read_excel('D:/1.xlsx', dtype={"phone":str}) >>> df phone 0 18373827382 1 18373824382 2 18373827382 3 18373427382 4 18373857382 5 18373827382 6 18373427382 7 18373817382 # 代码也很简单，只是分别取手机号的 # 前三位和后四位并添加*号拼接 >>> df['phone_replace']=df['phone'].str[0:3] + "****" + df['phone'].str[7:] >>> df phone phone_replace 0 18373827382 183****7382 1 18373824382 183****4382 2 18373827382 183****7382 3 18373427382 183****7382 4 18373857382 183****7382 5 18373827382 183****7382 6 18373427382 183****7382 7 18373817382 183****7382

var phone='13511115678'; //方法一 var newphone=phone.substr(0, 3) + '****' + phone.substr(phone.length - 4); //方法二 var newphone= phone.replace(phone.substr(3, 4),"****") //方法三 var newphone=phone.replace(/(\d{3})\d{4}(\d{4})/, '$1****$3'); //方法四 var newphone=phone.replace( /([0-9]{3})([0-9]{4})([0-9]{4})/,"$1****$3")