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Python开发桌面小程序功能_python_

2023-05-26 533人已围观

简介 Python开发桌面小程序功能_python_

当使用桌面应用程序的时候，
有没有那么一瞬间，
想学习一下桌面应用程序开发？
建议此次课程大家稍作了解不要浪费太多时间，
因为没有哪家公司会招聘以为Python程序员开发桌面程序吧？

开发环境：

  • Python 3.6
  • Pycharm

代码

界面设置

导入模块

import tkinter as tk

实例化一个窗体对象

root = tk.Tk()

标题

root.title('计算器')

大小以及出现的位置

root.geometry("295x280+150+150")

透明度

root.attributes("-alpha", 0.9)

背景

root["background"] = "#ffffff"

标签

lable1 = tk.Label(root, textvariable=result_num, width=20, height=2, font=('宋体', 20), justify='left', background='#ffffff', anchor='se')

布局

lable1.grid(padx=4, pady=4, row=0, column=0, columnspan=4)

按钮

button_clear = tk.Button(root, text='C', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: clear()) button_back = tk.Button(root, text='←', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: back()) button_division = tk.Button(root, text='/', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('/')) button_multiplication = tk.Button(root, text='x', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('*')) button_clear .grid(padx=4, row=1, column=0) button_back .grid(padx=4, row=1, column=1) button_division .grid(padx=4, row=1, column=2) button_multiplication .grid(padx=4, row=1, column=3) button_seven = tk.Button(root, text='7', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('7')) button_eight = tk.Button(root, text='8', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('8')) button_nine = tk.Button(root, text='9', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('9')) button_subtraction = tk.Button(root, text='—', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('-')) button_seven .grid(padx=4, row=2, column=0) button_eight .grid(padx=4, row=2, column=1) button_nine .grid(padx=4, row=2, column=2) button_subtraction .grid(padx=4, row=2, column=3) button_four = tk.Button(root, text='4', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('4')) button_four.grid(padx=4, pady=4, row=3, column=0) button_five = tk.Button(root, text='5', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('5')) button_five.grid(padx=4, row=3, column=1) button_six = tk.Button(root, text='6', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('6')) button_six.grid(padx=4, row=3, column=2) button_addition = tk.Button(root, text='+', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('+')) button_addition.grid(padx=4, row=3, column=3) button_one = tk.Button(root, text='1', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('1')) button_one.grid(padx=4, row=4, column=0) button_two = tk.Button(root, text='2', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('2')) button_two.grid(padx=4, row=4, column=1) button_three = tk.Button(root, text='3', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('3')) button_three.grid(padx=4, row=4, column=2) button_equal = tk.Button(root, text='=', width=5, height=3, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: equal()) button_equal.grid(padx=4, row=4, rowspan=5, column=3) button_zero = tk.Button(root, text='0', width=12, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('0')) button_zero.grid(padx=4, pady=4, row=5, column=0, columnspan=2) button_decimal = tk.Button(root, text='.', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('.')) button_decimal.grid(padx=4, row=5, column=2)

现在得出界面效果

请添加图片描述

功能

添加数字

def append_num(i): lists.append(i) result_num.set(''.join(lists))

选择运算符号

def operator(i): if len(lists) > 0: if lists[-1] in ['+', '-', '*', '/']: lists[-1] = i else: lists.append(i) result_num.set(''.join(lists))

清零

def clear(): lists.clear() result_num.set(0)

退格

def back(): del lists[-1] result_num.set(lists)

等号

def equal(): a = ''.join(lists) end_num = eval(a) result_num.set(end_num) lists.clear() lists.append(str(end_num))

定义一个列表收集输入的内容

lists = [] result_num = tk.StringVar() result_num.set(0)

最后运行代码，效果如下图

先试试

请添加图片描述

运算得出结果

请添加图片描述

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